tag:blogger.com,1999:blog-29632375.post8130990005439380006..comments2023-06-19T19:45:40.281-07:00Comments on vexorian's blog: TopCoder SRM 566: The road to blueUnknownnoreply@blogger.comBlogger9125tag:blogger.com,1999:blog-29632375.post-53746327665307849732013-01-18T06:13:13.130-08:002013-01-18T06:13:13.130-08:00Editorial coming soon.Editorial coming soon.vexoriannoreply@blogger.comtag:blogger.com,1999:blog-29632375.post-91811629141402501492013-01-18T06:11:54.867-08:002013-01-18T06:11:54.867-08:00No love for Div - II. :(No love for Div - II. :(kr0ynoreply@blogger.comtag:blogger.com,1999:blog-29632375.post-49743906541583048972013-01-13T18:34:34.455-08:002013-01-13T18:34:34.455-08:00Yeah that's basically what I said in the last ...Yeah that's basically what I said in the last paragraph. I actually figured that while writing that blog post. Before that the idea was completely gone. Then I went to the practice rooms and passed.<br /><br /><br />I think I might start to write the blog posts while I solve the problems.vexoriannoreply@blogger.comtag:blogger.com,1999:blog-29632375.post-21886536397274698282013-01-13T11:41:24.514-08:002013-01-13T11:41:24.514-08:00In the 500, you have to notice that because of sym...In the 500, you have to notice that because of symmetry, the number of paths (of length k) from city i to city j only depends on ((j - i) % numCities). Then you just need to store the number of paths (of length k) from city 0 to all cities instead of the matrix of all pairs number of paths.bloopsnoreply@blogger.comtag:blogger.com,1999:blog-29632375.post-60068983874929832542013-01-13T10:55:55.059-08:002013-01-13T10:55:55.059-08:00You didn't need to calculate binomial coeffici...You didn't need to calculate binomial coefficients - a star center with k possible legs contributes 2^k - k - 1 to the answer.dj3500noreply@blogger.comtag:blogger.com,1999:blog-29632375.post-73319853234464573202013-01-13T06:53:13.734-08:002013-01-13T06:53:13.734-08:00I usually use KawigiEdit for parsing the problem s...I usually use KawigiEdit for parsing the problem statement and later use this code along with test code to use in my favourite editor Codeblocks. You can also do so.PRAVEEN DHINWAnoreply@blogger.comtag:blogger.com,1999:blog-29632375.post-41436813222778594122013-01-13T03:20:32.680-08:002013-01-13T03:20:32.680-08:00Absolutely same thing with me on the 250! Luckily ...Absolutely same thing with me on the 250! Luckily I found out about the triangle being valid in 50 minutes and the 250 was my first opened problem.<br />Change the strategy, vexorian. It has nothing to do with you being slow, 250-ers are getting harder and harder.zdravko_bnoreply@blogger.comtag:blogger.com,1999:blog-29632375.post-12689940069608654072013-01-12T14:41:13.565-08:002013-01-12T14:41:13.565-08:00KawigiEdit 1.8 (The pivanov version). But it force...KawigiEdit 1.8 (The pivanov version). But it forces its own editor, probably you prefer to use your favorite code editor.<br /><br /><br />You can set up plugins using the practice rooms so that you do not lose time setting them up during the match.vexoriannoreply@blogger.comtag:blogger.com,1999:blog-29632375.post-4791136320091705832013-01-12T14:31:50.091-08:002013-01-12T14:31:50.091-08:00The whole thing is impossible. I am only Division ...The whole thing is impossible. I am only Division 2 (somewhere down near the bottom) but I agree, we have to set our sights higher than the 250 problem. The trouble is, Division 2, 250 is the only one I ever solve.<br />I've given up challenging other people's work. I'll wait 'til I have a clue what I'm doing, maybe in five years. <br />I have TZTester working now but not on time for today's SRM. Do you use it? What other plugins (if any) do you use?Redwolfenoreply@blogger.com